a>b>c,a+b+c=0则c/a的取值范围是

-2 < c/a < -1/2
a+b+c=0 又a>b>c
==> 当b取a时，等式比0大
2a+c>0
==> c/a<-1/2
==> 当b取c时，等式比0小
a+2c<0
==> c/a> -2

所以: -2 < c/a < -1/2

a+b+c=0
==> b+c=-a
==> (b+c)/a=-1
==> c/a+b/a=-1
==> c/a=-b/a-1

又a>b>c,a+b+c=0
则c/a<0,b/a<1 ==> -b/a>-1 ==> -b/a-1>-2
所以: -2<c/a<0